Solve the problem.
-A fair spinner has regions numbered 1 through 18. What is the probability that the spinner will stop on an even number or a multiple of 3?
A) 15

B) $\frac { 1 } { 3 }$

C) $\frac { 2 } { 3 }$

D) 1

Question

Solve the problem.
-A fair spinner has regions numbered 1 through 18. What is the probability that the spinner will stop on an even number or a multiple of 3? 
A) 15

B) $\frac { 1 } { 3 }$

C) $\frac { 2 } { 3 }$

D) 1

Quizplus · Accepted Answer

The even numbers between 1 and 18 are 2, 4, 6, 8, 10, 12, 14, 16, and 18, making 9 even numbers. The multiples of 3 between 1 and 18 are 3, 6, 9, 12, 15, and 18, making 6 multiples of 3. However, 6 and 12 are both even and multiples of 3, so they are counted twice if we simply add the counts. Therefore, there are 9 (even numbers) + 6 (multiples of 3) - 2 (duplicates) = 13 unique numbers that are either even or multiples of 3 out of 18. Thus, the probability is 13/18, which simplifies to approximately 2/3 when considering the closest answer choice.

Solve the Problem 13\frac { 1 } { 3 }31​ C) 23\frac { 2 } { 3 }32​

Solve the Problem $\frac { 1 } { 3 }$ C) $\frac { 2 } { 3 }$