Solved

Graph the Equation $\frac{y}{6}=\sqrt{1+\frac{x^{2}}{16}}$ A) $( \infty , \infty ) ; ( \infty , - 6 ] ;$

Question 135

Multiple Choice

Graph the equation. Give the domain and range. Identify whether the equation is a function.
- $\frac{y}{6}=\sqrt{1+\frac{x^{2}}{16}}$
$Graph the equation. Give the domain and range. Identify whether the equation is a function. - \frac{y}{6}=\sqrt{1+\frac{x^{2}}{16}} A) ( \infty , \infty ) ; ( \infty , - 6 ] ; not a function B) ( \infty , \infty ) ; [ 1 , \infty ) ; function C) ( \infty , \infty ) ; ( \infty , - 1 ] ; not a function D) ( \infty , \infty ) ; [ 6 , \infty ) ; function$

A)
$Graph the equation. Give the domain and range. Identify whether the equation is a function. - \frac{y}{6}=\sqrt{1+\frac{x^{2}}{16}} A) ( \infty , \infty ) ; ( \infty , - 6 ] ; not a function B) ( \infty , \infty ) ; [ 1 , \infty ) ; function C) ( \infty , \infty ) ; ( \infty , - 1 ] ; not a function D) ( \infty , \infty ) ; [ 6 , \infty ) ; function$
$( \infty , \infty ) ; ( \infty , - 6 ] ;$ not a function

B)
$Graph the equation. Give the domain and range. Identify whether the equation is a function. - \frac{y}{6}=\sqrt{1+\frac{x^{2}}{16}} A) ( \infty , \infty ) ; ( \infty , - 6 ] ; not a function B) ( \infty , \infty ) ; [ 1 , \infty ) ; function C) ( \infty , \infty ) ; ( \infty , - 1 ] ; not a function D) ( \infty , \infty ) ; [ 6 , \infty ) ; function$
$( \infty , \infty )$ ; $[ 1 , \infty )$ ; function

C)
$Graph the equation. Give the domain and range. Identify whether the equation is a function. - \frac{y}{6}=\sqrt{1+\frac{x^{2}}{16}} A) ( \infty , \infty ) ; ( \infty , - 6 ] ; not a function B) ( \infty , \infty ) ; [ 1 , \infty ) ; function C) ( \infty , \infty ) ; ( \infty , - 1 ] ; not a function D) ( \infty , \infty ) ; [ 6 , \infty ) ; function$
$( \infty , \infty ) ; ( \infty , - 1 ]$ ; not a function

D)
$Graph the equation. Give the domain and range. Identify whether the equation is a function. - \frac{y}{6}=\sqrt{1+\frac{x^{2}}{16}} A) ( \infty , \infty ) ; ( \infty , - 6 ] ; not a function B) ( \infty , \infty ) ; [ 1 , \infty ) ; function C) ( \infty , \infty ) ; ( \infty , - 1 ] ; not a function D) ( \infty , \infty ) ; [ 6 , \infty ) ; function$

$( \infty , \infty ) ; [ 6 , \infty )$ ; function