Solve the problem.
-How many liters of a 30% alcohol solution must be mixed with 90 liters of a 50% solution to get a 40% solution?
A) 180 L
B) 18 L
C) 90 L
D) 9 L

Name: Solve the problem. -How many liters of a 30% alcohol solution must be mixed with 90 liters of a 50% solution to get a 40% solution? A) 180 L B) 18 L C) 90 L D) 9 L
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Question

Quizplus · Accepted Answer

To solve this, let x be the amount of 30% solution needed. The equation is 0.30x + 0.50*90 = 0.40(x + 90). Solving for x gives x = 90 liters.

Solve the Problem. -How Many Liters of a 30% Alcohol Solution Must Be