Solve the problem.
-How much pure acid should be mixed with 8 gallons of a 50% acid solution in order to get an 80% acid solution?
A) 32 gal
B) 20 gal
C) 12 gal
D) 4 gal

Question

Quizplus · Accepted Answer

The 8 gallons of 50% solution contain 4 gallons of pure acid. To achieve an 80% solution, let x be the gallons of pure acid added. The equation is $0.50(8) + x = 0.80(8 + x)$. Solving gives $x = 12$ gallons.

Solve the Problem. -How Much Pure Acid Should Be Mixed with 8 Gallons