Solve the equation for the indicated variable. Assume no denominator is 0.
-$2 x ^ { 2 } - 4 x y + 3 y ^ { 2 } = 1$, for $y$

A) $y = \frac { 2 x \pm 4 \sqrt { 3 - 2 x ^ { 2 } } } { 3 }$

B) $y = \frac { 2 x \pm \sqrt { 3 - 2 x ^ { 2 } } } { 3 }$

C) $y = \frac { 2 x \pm \sqrt { 6 - 4 x ^ { 2 } } } { 3 }$

D) $y = \frac { 2 x \pm 2 \sqrt { 3 - 2 x ^ { 2 } } } { 3 }$

Question

Solve the equation for the indicated variable. Assume no denominator is 0.
-$2 x ^ { 2 } - 4 x y + 3 y ^ { 2 } = 1$, for $y$

A) $y = \frac { 2 x \pm 4 \sqrt { 3 - 2 x ^ { 2 } } } { 3 }$

B) $y = \frac { 2 x \pm \sqrt { 3 - 2 x ^ { 2 } } } { 3 }$

C) $y = \frac { 2 x \pm \sqrt { 6 - 4 x ^ { 2 } } } { 3 }$

D) $y = \frac { 2 x \pm 2 \sqrt { 3 - 2 x ^ { 2 } } } { 3 }$

Quizplus · Accepted Answer

The Answer of Solve the equation for the indicated variable. Assume no denominator is 0.
-$2 x ^ { 2 } - 4 x y + 3 y ^ { 2 } = 1$, for $y$

A) $y = \frac { 2 x \pm 4 \sqrt { 3 - 2 x ^ { 2 } } } { 3 }$

B) $y = \frac { 2 x \pm \sqrt { 3 - 2 x ^ { 2 } } } { 3 }$

C) $y = \frac { 2 x \pm \sqrt { 6 - 4 x ^ { 2 } } } { 3 }$

D) $y = \frac { 2 x \pm 2 \sqrt { 3 - 2 x ^ { 2 } } } { 3 }$

Solve the Equation for the Indicated Variable 2x2−4xy+3y2=12 x ^ { 2 } - 4 x y + 3 y ^ { 2 } = 12x2−4xy+3y2=1