Solve the problem.
-The position of an object moving in a straight line is given by s $\mathrm { s } = 2 \mathrm { t } ^ { 2 } - 3 \mathrm { t }$ where s is in meters and t 281) is the time in seconds the object has been in motion. How long (to the nearest tenth) will it take the
Object to move 20 meters?
A) 21.0 sec
B) 3.8 sec
C) 74.0 sec
D) 4.0 sec

Question

Quizplus · Accepted Answer

To find the time it takes for the object to move 20 meters, set s = 20 and solve the equation 2t^2 - 3t = 20. Rearranging gives 2t^2 - 3t - 20 = 0. Solving this quadratic equation using the quadratic formula gives t ≈ 4.0 seconds.

Solve the Problem s=2t2−3t\mathrm { s } = 2 \mathrm { t } ^ { 2 } - 3 \mathrm { t }s=2t2−3t

Solve the Problem $\mathrm { s } = 2 \mathrm { t } ^ { 2 } - 3 \mathrm { t }$