Decide what values of the variable cannot possibly be solutions for the equation.
-$$\left( x ^ { 2 } - 3 \right) ^ { 1 / 2 } - ( x + 3 ) ^ { 1 / 2 } = 0$$
A) $\{ 2,3 \}$
B) $\{ - 3 \}$
C) $\{ - 3,3 \}$
D) $\{ - 2,3 \}$

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The Answer of Decide what values of the variable cannot possibly be solutions for the equation.
-$$\left( x ^ { 2 } - 3 \right) ^ { 1 / 2 } - ( x + 3 ) ^ { 1 / 2 } = 0$$
A) $\{ 2,3 \}$
B) $\{ - 3 \}$
C) $\{ - 3,3 \}$
D) $\{ - 2,3 \}$

Decide What Values of the Variable Cannot Possibly Be Solutions (x2−3)1/2−(x+3)1/2=0\left( x ^ { 2 } - 3 \right) ^ { 1 / 2 } - ( x + 3 ) ^ { 1 / 2 } = 0(x2−3)1/2−(x+3)1/2=0

Decide What Values of the Variable Cannot Possibly Be Solutions $\left( x ^ { 2 } - 3 \right) ^ { 1 / 2 } - ( x + 3 ) ^ { 1 / 2 } = 0$