Solve the equation.
-$$\left| \frac { 7 x + 2 } { 4 x + 9 } \right| = 7$$
A) $\left\{ - \frac { 61 } { 21 } , - \frac { 13 } { 7 } \right\}$

B) $\left\{ - \frac { 65 } { 21 } , - \frac { 61 } { 35 } \right\}$

C) $\left\{ \frac { 5 } { 7 } , - \frac { 9 } { 7 } \right\}$

D) $\left\{ \frac { 61 } { 35 } , \frac { 3 } { 7 } \right\}$

Question

Solve the equation.
-$$\left| \frac { 7 x + 2 } { 4 x + 9 } \right| = 7$$
A) $\left\{ - \frac { 61 } { 21 } , - \frac { 13 } { 7 } \right\}$

B) $\left\{ - \frac { 65 } { 21 } , - \frac { 61 } { 35 } \right\}$

C) $\left\{ \frac { 5 } { 7 } , - \frac { 9 } { 7 } \right\}$

D) $\left\{ \frac { 61 } { 35 } , \frac { 3 } { 7 } \right\}$

Quizplus · Accepted Answer

To solve the equation $\left| \frac { 7 x + 2 } { 4 x + 9 } \right| = 7$, we consider two cases due to the absolute value:1. $\frac { 7 x + 2 } { 4 x + 9 } = 7$Solving for $x$, we get $7x + 2 = 28x + 63$, leading to $x = -\frac{61}{21}$.2. $\frac { 7 x + 2 } { 4 x + 9 } = -7$Solving for $x$, we get $7x + 2 = -28x - 63$, leading to $x = -\frac{13}{7}$.Thus, the solution set is $\left\{ - \frac { 61 } { 21 } , - \frac { 13 } { 7 } \right\}$.

Solve the Equation ∣7x+24x+9∣=7\left| \frac { 7 x + 2 } { 4 x + 9 } \right| = 7​4x+97x+2​​=7

Solve the Equation $\left| \frac { 7 x + 2 } { 4 x + 9 } \right| = 7$