Consider the following printout.
HYPOTHESIS: VARIANCE $X = x$
$$X = \text { gpa }$$
SAMPLE MEAN OF $X = 2.5516$
SAMPLE VARIANCE OF X $= .24000$
SAMPLE SIZE OF $X = 157$
HYPOTHESIZED VALUE $( x ) = 2.7$
VARIANCE $X - x = - .1484$
$$z = - 3.79558$$
Is this a large enough sample for this analysis to work?
A) Yes, since the $n p 15$ and $n q 15$.
B) Yes, since $n = 157$, which is greater than 30 .
C) No.
D) Yes, since the population of GPA scores is approximately normally distributed.

Question

Consider the following printout. 
HYPOTHESIS: VARIANCE $X = x$
$$X = \text { gpa }$$
SAMPLE MEAN OF $X = 2.5516$
SAMPLE VARIANCE OF X $= .24000$
SAMPLE SIZE OF $X = 157$
HYPOTHESIZED VALUE $( x ) = 2.7$
VARIANCE $X - x = - .1484$
$$z = - 3.79558$$
Is this a large enough sample for this analysis to work?
A) Yes, since the $n p > 15$ and $n q > 15$.
B) Yes, since $n = 157$, which is greater than 30 .
C) No.
D) Yes, since the population of GPA scores is approximately normally distributed.

Quizplus · Accepted Answer

The sample size of 157 is greater than 30, which is generally considered large enough for the Central Limit Theorem to apply, allowing for normal approximation.

Consider the Following Printout X=xX = xX=x X= gpa X = \text { gpa }X= gpa

Consider the Following Printout $X = x$ $X = \text { gpa }$