Consider the following printout.
HYPOTHESIS: MEAN X $= \mathrm { x }$
$$X = \text { gpa }$$
SAMPLE MEAN OF $X = 2.9397$
SAMPLE VARIANCE OF $X = 0.246823$
SAMPLE SIZE OF $X = 167$
HYPOTHESIZED VALUE $( \mathrm { x } ) = 3$
$$\begin{aligned}
\text { MEAN X-x } & = - 0.0603 \
z & = - 1.56849
\end{aligned}$$
Suppose a two-tailed test is desired. Find the $p$-value for the test.
A) $p = 0.0582$
B) $p = 0.9418$
C) $p = 0.1164$
D) $p = 0.8836$

Question

Consider the following printout.
 HYPOTHESIS: MEAN X $= \mathrm { x }$
$$X = \text { gpa }$$
SAMPLE MEAN OF $X = 2.9397$
SAMPLE VARIANCE OF $X = 0.246823$
SAMPLE SIZE OF $X = 167$
HYPOTHESIZED VALUE $( \mathrm { x } ) = 3$
$$\begin{aligned}
\text { MEAN X-x } & = - 0.0603 \
z & = - 1.56849
\end{aligned}$$
Suppose a two-tailed test is desired. Find the $p$-value for the test.
A) $p = 0.0582$
B) $p = 0.9418$
C) $p = 0.1164$
D) $p = 0.8836$

Quizplus · Accepted Answer

The z-value of -1.56849 corresponds to a p-value of 0.0582 for one tail. Since it's a two-tailed test, the p-value is doubled, resulting in 0.1164.

Consider the Following Printout =x= \mathrm { x }=x X= gpa X = \text { gpa }X= gpa

Consider the Following Printout $= \mathrm { x }$ $X = \text { gpa }$