Suppose a random variable $x$ is best described by a normal distribution with $\mu = 60$ and $\sigma = 9$. Find the $\mathrm { z }$-score that corresponds to the value $x = 96$.
A) 36
B) $\frac { 5 } { 3 }$
C) 9
D) 4

Question

Quizplus · Accepted Answer

The z-score is calculated using the formula $ z = \frac{x - \mu}{\sigma} $. Substituting the given values, $ z = \frac{96 - 60}{9} = \frac{36}{9} = 4 $.

Suppose a Random Variable xxx Is Best Described by a Normal Distribution With

Suppose a Random Variable $x$ Is Best Described by a Normal Distribution With