Solve the problem.
-A racetrack curve is banked so that the outside of the curve is slightly elevated or inclined above the inside of the curve. This inclination is called the elevation of the track. The maximum speed on the track in miles per
Hour is given by $$\sqrt { r ( 29000 + 41000 \tan \theta ) }$$ where r is the radius of the track in miles and θ is the elevation in degrees. Find the maximum speed for a
Racetrack with an elevation of 26° and a radius of 0.6 miles. Round to the nearest mile per hour.
A) 37,953 mph
B) 59,899 mph
C) 193 mph
D) 171 mph

Question

Quizplus · Accepted Answer

To find the maximum speed, substitute $r = 0.6$ miles and $\theta = 26^\circ$ into the given formula. First, calculate $\tan(26^\circ)$, then plug it into the formula along with $r = 0.6$ and solve for the speed. After performing the calculations, rounding to the nearest mile per hour gives approximately 171 mph.

Solve the Problem r(29000+41000tan⁡θ)\sqrt { r ( 29000 + 41000 \tan \theta ) }r(29000+41000tanθ)​

Solve the Problem $\sqrt { r ( 29000 + 41000 \tan \theta ) }$