Solve the problem.
-For what numbers $x , 0 \leq x \leq 2 \pi$, does $\sin x = - 1$ ?
A) $\pi$
B) $\frac { \pi } { 2 } , \frac { 3 \pi } { 2 }$
C) $\frac { 3 \pi } { 2 }$
D) none

Name: Solve the problem. -For what numbers $x , 0 \leq x \leq 2 \pi$, does $\sin x = - 1$ ? A) $\pi$ B) $\frac { \pi } { 2 } , \frac { 3 \pi } { 2 }$ C) $\frac { 3 \pi } { 2 }$ D) none
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Question

Quizplus · Accepted Answer

$\sin x = -1$ occurs at $x = \frac{3\pi}{2}$ within the given domain $0 \leq x \leq 2\pi$.

Solve the Problem x,0≤x≤2πx , 0 \leq x \leq 2 \pix,0≤x≤2π

Solve the Problem $x , 0 \leq x \leq 2 \pi$