Solve Nonlinear Systems By Addition
-x2 - 3y2 = 1 4x2 + 3y2 = 19
A) {(2, 1), (-2, 1), (2, -1), (-2, -1)}
B) {(2, 1), (-2, -1)}
C) {(1, 2), (-1, 2), (1, -2), (-1, -2)}
D) {(1, 2), (-1, -2)}

Question

Quizplus · Accepted Answer

Adding the two equations eliminates $y^2$, resulting in $5x^2 = 20$, which simplifies to $x^2 = 4$. Solving for $x$ gives $x = \pm2$. Substituting $x$ back into one of the original equations allows solving for $y$, resulting in $y = \pm1$. Thus, all four combinations of $(\pm2, \pm1)$ are solutions.

Solve Nonlinear Systems by Addition