Complete the identity.
-$\frac { ( \tan x + 1 ) ( \tan x + 1 ) - \sec ^ { 2 } x } { \tan x } =$ ?
A) 2
B) 1
C) 0
D) $\tan x$

Question

Quizplus · Accepted Answer

The expression simplifies as follows: $(\tan x + 1)^2 - \sec^2 x = \tan^2 x + 2\tan x + 1 - \sec^2 x$. Using the identity $\sec^2 x = \tan^2 x + 1$, the expression becomes $\tan^2 x + 2\tan x + 1 - (\tan^2 x + 1) = 2\tan x$. Dividing by $\tan x$ gives 2.

Complete the Identity (tan⁡x+1)(tan⁡x+1)−sec⁡2xtan⁡x=\frac { ( \tan x + 1 ) ( \tan x + 1 ) - \sec ^ { 2 } x } { \tan x } =tanx(tanx+1)(tanx+1)−sec2x​=

Complete the Identity $\frac { ( \tan x + 1 ) ( \tan x + 1 ) - \sec ^ { 2 } x } { \tan x } =$