First, write the value(s) that make the denominator(s) zero. Then solve the equation.
-$$\frac { x - 1 } { 4 x } + 8 = \frac { x + 6 } { x }$$
A) $x \neq 0 ; \left\{ \frac { 25 } { 29 } \right\}$
B) $x \neq 0 ; \left\{ - \frac { 17 } { 3 } \right\}$
C) $x \neq 0,4 ; \left\{ \frac { 25 } { 29 } \right\}$
D) No restrictions; $\left\{ \frac { 7 } { 32 } \right\}$

Question

Quizplus · Accepted Answer

The denominators are $4x$ and $x$, so $x \neq 0$ to avoid division by zero. Solving the equation gives $x = \frac{25}{29}$.

First, Write the Value(s) That Make the Denominator(s) Zero x−14x+8=x+6x\frac { x - 1 } { 4 x } + 8 = \frac { x + 6 } { x }4xx−1​+8=xx+6​

First, Write the Value(s) That Make the Denominator(s) Zero $\frac { x - 1 } { 4 x } + 8 = \frac { x + 6 } { x }$