Use the five-step strategy for solving word problems to find the number or numbers described in the following
exercise.
-$y _ { 1 } = \frac { 1 } { x + 2 } , y _ { 2 } = \frac { 1 } { x - 2 } , y _ { 3 } = \frac { 1 } { x ^ { 2 } - 4 }$, and the difference between 9 times $y _ { 1 }$ and 7 times $y _ { 2 }$ is the product of 10 and $y 3$.
A) $\{ 21 \}$
B) $\{ - 21 \}$
C) $\{ \sqrt { 57 } \}$
D) $\{ 42 \}$

Question

Quizplus · Accepted Answer

The given equations are $y_1 = \frac{1}{x+2}$, $y_2 = \frac{1}{x-2}$, and $y_3 = \frac{1}{x^2-4}$. The problem states that $9y_1 - 7y_2 = 10y_3$. Substituting the expressions for $y_1$, $y_2$, and $y_3$ into this equation and solving for $x$ yields $x = 21$.

Use the Five-Step Strategy for Solving Word Problems to Find y1=1x+2,y2=1x−2,y3=1x2−4y _ { 1 } = \frac { 1 } { x + 2 } , y _ { 2 } = \frac { 1 } { x - 2 } , y _ { 3 } = \frac { 1 } { x ^ { 2 } - 4 }y1​=x+21​,y2​=x−21​,y3​=x2−41​

Use the Five-Step Strategy for Solving Word Problems to Find $y _ { 1 } = \frac { 1 } { x + 2 } , y _ { 2 } = \frac { 1 } { x - 2 } , y _ { 3 } = \frac { 1 } { x ^ { 2 } - 4 }$