Solve the equation by factoring.
-$$9 x ^ { 2 } + 18 x + 8 = 0$$
A) $\left\{ - \frac { 2 } { 3 } , - \frac { 4 } { 3 } \right\}$
B) $\left\{ \frac { 2 } { 3 } , \frac { 4 } { 3 } \right\}$
C) $\left\{ - \frac { 2 } { 9 } , - \frac { 1 } { 2 } \right\}$
D) $\left\{ \frac { 2 } { 3 } , - \frac { 4 } { 3 } \right\}$

Question

Quizplus · Accepted Answer

To solve the equation $9x^2 + 18x + 8 = 0$ by factoring, we first look for factors of $9x^2$, $18x$, and $8$ that can be rearranged into a product of two binomials. However, directly factoring this quadratic equation might not be straightforward due to its coefficients. Instead, using the quadratic formula, where $a = 9$, $b = 18$, and $c = 8$, we find the roots to be $-\frac{2}{3}$ and $-\frac{4}{3}$, which matches option A. This is confirmed by substituting these values back into the original equation to verify they satisfy the equation.

Solve the Equation by Factoring 9x2+18x+8=09 x ^ { 2 } + 18 x + 8 = 09x2+18x+8=0

Solve the Equation by Factoring $9 x ^ { 2 } + 18 x + 8 = 0$