Compute the discriminant. Then determine the number and type of solutions for the given equation.
-$$x ^ { 2 } - 7 x + 6 = 0$$
A) 25 ; two unequal real solutions
B) $- 73$; two complex imaginary solutions
C) 0 ; one real solution

Question

Quizplus · Accepted Answer

The discriminant of a quadratic equation $ax^2 + bx + c = 0$ is given by $D = b^2 - 4ac$. For the given equation, $a = 1$, $b = -7$, and $c = 6$, so $D = (-7)^2 - 4(1)(6) = 49 - 24 = 25$. Since $D > 0$, there are two unequal real solutions.

Compute the Discriminant x2−7x+6=0x ^ { 2 } - 7 x + 6 = 0x2−7x+6=0

Compute the Discriminant $x ^ { 2 } - 7 x + 6 = 0$