Compute the discriminant. Then determine the number and type of solutions for the given equation.
-$$4 x ^ { 2 } = - 2 x - 7$$
A) $- 108$; two complex imaginary solutions
B) 116; two unequal real solutions
C) 0 ; one real solution

Question

Quizplus · Accepted Answer

The discriminant of a quadratic equation $ax^2 + bx + c = 0$ is given by $D = b^2 - 4ac$. For the given equation $4x^2 + 2x + 7 = 0$, $a = 4$, $b = 2$, and $c = 7$, so the discriminant is $D = (2)^2 - 4(4)(7) = 4 - 112 = -108$. A negative discriminant indicates two complex imaginary solutions.

Compute the Discriminant 4x2=−2x−74 x ^ { 2 } = - 2 x - 74x2=−2x−7

Compute the Discriminant $4 x ^ { 2 } = - 2 x - 7$