Solve and check the equation.
-$2 x ^ { 7 / 2 } - 4 = 0$
A) $\{ \sqrt [ 7 ] { 4 } \}$
B) $\{ \sqrt [ 7 ] { 2 } \}$
C) $\left\{ \frac { 4 } { 7 } \right\}$
D) $\varnothing$

Question

Quizplus · Accepted Answer

To solve the equation $2x^{7/2} - 4 = 0$, add 4 to both sides to get $2x^{7/2} = 4$. Then divide both sides by 2 to get $x^{7/2} = 2$. To solve for $x$, raise both sides to the power of $2/7$, resulting in $x = 2^{2/7}$, which simplifies to $x = \sqrt[7]{4}$.

Solve and Check the Equation 2x7/2−4=02 x ^ { 7 / 2 } - 4 = 02x7/2−4=0

Solve and Check the Equation $2 x ^ { 7 / 2 } - 4 = 0$