Solve the problem.
-A formula used to determine the velocity $v$ in feet per second of an object (neglecting air resistance) after it has fallen a certain height is $\mathrm { v } = \sqrt { 2 g h }$, where $g$ is the acceleration due to gravity and $h$ is the height the object has fallen. If the acceleration $g$ due to gravity on Earth is approximately 32 feet per second per second, find the velocity of a bowling ball after it has fallen 40 feet. (Round to the nearest tenth.)
A) $50.6 \mathrm { ft }$ per $\mathrm { sec }$
B) $35.8 \mathrm { ft }$ per sec
C) $8.9 \mathrm { ft }$ per sec
D) $2560 \mathrm { ft }$ per sec

Question

Quizplus · Accepted Answer

Using the formula $v = \sqrt{2gh}$ with $g = 32 \, \text{ft/s}^2$ and $h = 40 \, \text{ft}$, we get $v = \sqrt{2 \times 32 \times 40} = \sqrt{2560} \approx 50.6 \, \text{ft/s}$.

Solve the Problem vvv In Feet Per Second of an Object (Neglecting Air Resistance)

Solve the Problem $v$ In Feet Per Second of an Object (Neglecting Air Resistance)