Solve the problem.
-When an object is dropped to the ground from a height of h meters, the time it takes for the object to reach the ground is given by the equation $t = \sqrt { \frac { h } { 4.9 } }$, where $t$ is measured in seconds. Solve the equation for h.
Use the result to determine the height from which an object was dropped if it hits the ground after falling for 3 seconds.
A) $\mathrm { h } = 4.9 \mathrm { t } ^ { 2 } ; 44.1 \mathrm {~m}$
B) $\mathrm { h } = 24.01 \mathrm { t } ; 72 \mathrm {~m}$
C) $h = 24.01 t ^ { 2 } ; 216.1 \mathrm {~m}$
D) $\mathrm { h } = 4.9 \mathrm { t } ; 14.7 \mathrm {~m}$

Question

Quizplus · Accepted Answer

Squaring both sides of the given equation $t = \sqrt { \frac { h } { 4.9 } }$ gives $t^2 = \frac{h}{4.9}$, which leads to $h = 4.9t^2$. Substituting $t = 3$ seconds into the equation gives $h = 4.9 \times 3^2 = 44.1$ meters.

Solve the Problem t=h4.9t = \sqrt { \frac { h } { 4.9 } }t=4.9h​​

Solve the Problem $t = \sqrt { \frac { h } { 4.9 } }$