A Large University Is Interested in Learning About the Average $\mu = 20$

A large university is interested in learning about the average time it takes students to drive to campus. The university sampled 238 students and asked each to provide the amount of time they spent traveling to campus. This variable, travel time, was then used to create a confidence interval and to conduct a test of hypothesis, both of which are shown in the printout below. One-Sample Z Test
Null Hypothesis: $\mu = 20$
Alternative Hyp: $\mu > 20$
$\quad$$\quad$$\quad$$\quad$$\quad$$\quad$$\quad$$\quad$$\quad$$95 \% \text { Conf Interval }$
$\text { Variable \quad Mean \quad SE \quad Lower \quad Upper\quad Z \quad P }$
$\begin{array} { l l l l l l } \text { Camera Price } 23.243 & 1.3133 & 20.669 & 25.817 & 2.47 & 0.0071 \end{array}$ Cases Included 238 What conclusion can be made from the test of hypothesis conducted in this printout? Begin each answer with, "When testing at ? = 0.01…"

A) …there is sufficient evidence to indicate that the average travel time of all students is equal to 20 minutes.
B) …there is insufficient evidence to indicate that the average travel time of all students exceeds 20 minutes.
C) …there is sufficient evidence to indicate that the average travel time of all students exceeds 20 minutes.
D) …there is insufficient evidence to indicate that the average travel time of all students is equal to 20 minutes.