Let t0 be a specific value of t. Find t0 such that the following statement is true: $$P \left( t \geq t _ { 0 } \right) = .025 \text { where df } = 20 \text {. }$$
A) 2.086
B) -2.086
C) 2.093
D) -2.093

Question

Quizplus · Accepted Answer

The correct answer is A because the t-value corresponding to a probability of 0.025 with 20 degrees of freedom is 2.086.

Let T0 Be a Specific Value of T P(t≥t0)=.025 where df =20. P \left( t \geq t _ { 0 } \right) = .025 \text { where df } = 20 \text {. }P(t≥t0​)=.025 where df =20.

Let T0 Be a Specific Value of T $P \left( t \geq t _ { 0 } \right) = .025 \text { where df } = 20 \text {. }$