Use the standard normal distribution to find $$\mathrm { P } ( \mathrm { z } 2.33 )$$ A) .0198 B) .9809 C) .7888 D) .0606

Question

Use the standard normal distribution to find $$\mathrm { P } ( \mathrm { z } < - 2.33 \text { or } \mathrm { z } > 2.33 )$$
A) .0198
B) .9809
C) .7888
D) .0606

Quizplus · Accepted Answer

The standard normal distribution is a bell-shaped curve with a mean of 0 and a standard deviation of 1. The area under the curve between any two z-scores is the probability that a randomly selected value from the distribution will fall between those two z-scores.The probability that a randomly selected value from the standard normal distribution will be less than -2.33 is 0.0107. The probability that a randomly selected value from the standard normal distribution will be greater than 2.33 is also 0.0107. Therefore, the probability that a randomly selected value from the standard normal distribution will be less than -2.33 or greater than 2.33 is 0.0107 + 0.0107 = 0.0214.

Use the Standard Normal Distribution to Find P(z<−2.33 or z>2.33)\mathrm { P } ( \mathrm { z } < - 2.33 \text { or } \mathrm { z } > 2.33 )P(z<−2.33 or z>2.33)

Use the Standard Normal Distribution to Find $\mathrm { P } ( \mathrm { z } < - 2.33 \text { or } \mathrm { z } > 2.33 )$