For any events A and B, $$P ( A \mid B ) + P \left( A \mid B ^ { c } \right) = 1$$ , meaning given that A occurs either B occurs or B does not occur.

Name: For any events A and B, \[P ( A \mid B ) + P \left( A \mid B ^ { c } \right) = 1\] , meaning given that A occurs either B occurs or B does not occur.
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Question

Quizplus · Accepted Answer

The equation $P ( A \mid B ) + P \left( A \mid B ^ { c } \right) = 1$ is incorrect because the probabilities of A given B and A given not B do not necessarily sum to 1.

For Any Events a and B P(A∣B)+P(A∣Bc)=1P ( A \mid B ) + P \left( A \mid B ^ { c } \right) = 1P(A∣B)+P(A∣Bc)=1

For Any Events a and B $P ( A \mid B ) + P \left( A \mid B ^ { c } \right) = 1$