A human gene carries a certain disease from a mother to her child with a probability rate of 0.47. That is, there is a 47% chance that the child becomes infected with the disease. Suppose a female carrier of the gene has five children. Assume that the infections, or lack thereof, are independent of one another. Find the probability that all five of the children get the disease from their mother.

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Quizplus · Accepted Answer

The probability of a child getting the disease is 0.47. The probability of a child not getting the disease is 1 - 0.47 = 0.53. The probability of all five children getting the disease is (0.47)^5 = 0.023.

A Human Gene Carries a Certain Disease from a Mother