A basketball player has an 80% chance of making the first free-throw he shoots. If he makes the first free-throw shot, then he has a 90% chance of making the second free-throw he shoots. If he misses the first free-throw shot, then he only has a 70% chance of making the second free-throw he shoots. Suppose this player has been awarded two free-throw shots. Find the probability that he makes at least one of the two shots.
A) 0.72
B) 0.94
C) 0.86
D) 0.80

Question

Quizplus · Accepted Answer

The probability of making at least one shot is 1 minus the probability of missing both shots. The probability of missing the first shot is 0.2, and the probability of missing the second shot given the first is missed is 0.3. So, the probability of missing both shots is 0.2 * 0.3 = 0.06. Therefore, the probability of making at least one shot is 1 - 0.06 = 0.94.

A Basketball Player Has an 80% Chance of Making the First