Solved

Give a Rule for the Piecewise-Defined Function $f ( x ) = \left\{ \begin{array} { l l } 5 & \text { if } x \leq 0 \\ - x & \text { if } x > 0 \end{array} ; \right.$

Question 369

Multiple Choice

Give a rule for the piecewise-defined function. Then give the domain and range.
- $Give a rule for the piecewise-defined function. Then give the domain and range. - A) f ( x ) = \left\{ \begin{array} { l l } 5 & \text { if } x \leq 0 \\ - x & \text { if } x > 0 \end{array} ; \right. Domain: ( \infty , \infty ) , Range: ( \infty , 0 ) \cup \{ 5 \} B) f ( x ) = \left\{ \begin{array} { l } 5 \text { if } x < 0 \\ x \text { if } x \geq 0 \end{array} ; \right. Domain: ( \infty , 0 ] \cup ( 5 ) , Range: ( \infty , \infty ) C) f ( x ) = \left\{ \begin{array} { l l } 5 & \text { if } x < 0 \\ - 5 x & \text { if } x \geq 0 \end{array} ; \right. Domain: ( \infty , 0 ) \cup \{ 5 \} , Range: ( \infty , \infty ) D) f ( x ) = \left\{ \begin{array} { l l } 5 & \text { if } x < 0 \\ - x & \text { if } x \geq 0 \end{array} ; \right. Domain: ( \infty , \infty ) , Range: ( \infty , 0 ] \cup \{ 5 \}$

A) $f ( x ) = \left\{ \begin{array} { l l } 5 & \text { if } x \leq 0 \\ - x & \text { if } x > 0 \end{array} ; \right.$ Domain: $( \infty , \infty )$ , Range: $( \infty , 0 ) \cup \{ 5 \}$
B) $f ( x ) = \left\{ \begin{array} { l } 5 \text { if } x < 0 \\ x \text { if } x \geq 0 \end{array} ; \right.$ Domain: $( \infty , 0 ] \cup ( 5 )$ , Range: $( \infty , \infty )$
C) $f ( x ) = \left\{ \begin{array} { l l } 5 & \text { if } x < 0 \\ - 5 x & \text { if } x \geq 0 \end{array} ; \right.$ Domain: $( \infty , 0 ) \cup \{ 5 \}$ , Range: $( \infty , \infty )$
D) $f ( x ) = \left\{ \begin{array} { l l } 5 & \text { if } x < 0 \\ - x & \text { if } x \geq 0 \end{array} ; \right.$ Domain: $( \infty , \infty )$ , Range: $( \infty , 0 ] \cup \{ 5 \}$