Solve for y.
-$$10 y + x ^ { 2 } = x + 8$$
A) $y = x + 8 - x ^ { 2 }$
B) $y = x ^ { 2 } - x - 8$
C) $y = \frac { x + 8 - x ^ { 2 } } { 10 }$
D) $y = \frac { x ^ { 2 } - x - 8 } { 10 }$

Question

Quizplus · Accepted Answer

To solve for $y$, isolate $y$ on one side of the equation: $10y = x + 8 - x^2$. Then, divide both sides by 10 to get $y = \frac{x + 8 - x^2}{10}$.

Solve for Y 10y+x2=x+810 y + x ^ { 2 } = x + 810y+x2=x+8

Solve for Y $10 y + x ^ { 2 } = x + 8$