Solve the problem.
-In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took $\frac { 1 } { 8 }$ hour longer. How far did she travel to the appointment?
A) 20 mi
B) 7.5 mi
C) 0.5 mi
D) 25 mi

Question

Quizplus · Accepted Answer

The distance to the appointment can be found using the formula $d = rt$, where $d$ is distance, $r$ is rate, and $t$ is time. Let $t$ be the time it took for the morning trip. The return trip took $t + \frac{1}{8}$ hours. Since distance is the same for both trips, we can set up the equation: $50t = 40(t + \frac{1}{8})$. Solving for $t$ gives $t = \frac{1}{2}$ hour. Substituting $t$ back into $d = rt$ for the morning trip gives $d = 50 \times \frac{1}{2} = 25$ miles.

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