Solve the equation using the quadratic formula.
-$$4 x ^ { 2 } + 8 x + 2 = 0$$
A) $\left\{ \frac { - 2 \pm \sqrt { 6 } } { 2 } \right\}$
B) $\left\{ \frac { - 2 \pm \sqrt { 2 } } { 8 } \right\}$
C) $\left\{ \frac { - 8 \pm \sqrt { 2 } } { 2 } \right\}$
D) $\left\{ \frac { - 2 \pm \sqrt { 2 } } { 2 } \right\}$

Question

Quizplus · Accepted Answer

The quadratic formula is $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. For the equation $4x^2 + 8x + 2 = 0$, $a = 4$, $b = 8$, and $c = 2$. Plugging these into the formula gives $\frac{-8 \pm \sqrt{8^2 - 4 \cdot 4 \cdot 2}}{2 \cdot 4} = \frac{-8 \pm \sqrt{64 - 32}}{8} = \frac{-8 \pm \sqrt{32}}{8} = \frac{-8 \pm 4\sqrt{2}}{8} = \frac{-2 \pm \sqrt{2}}{2}$.

Solve the Equation Using the Quadratic Formula 4x2+8x+2=04 x ^ { 2 } + 8 x + 2 = 04x2+8x+2=0

Solve the Equation Using the Quadratic Formula $4 x ^ { 2 } + 8 x + 2 = 0$