The sum of the squares of two consecutive even integers is 52. Find the integers.
A) 4,6
B) $- 4 , - 6$
C) 4,6 or $- 4 , - 6$
D) $5 , - 7$

Question

The sum of the squares of two consecutive even integers is 52. Find the integers. 
A) 4,6
B) $- 4 , - 6$
C) 4,6 or $- 4 , - 6$
D) $5 , - 7$

Quizplus · Accepted Answer

The two consecutive even integers can be represented as $x$ and $x+2$. Their squares sum up to 52, so we have $x^2 + (x+2)^2 = 52$. Solving this equation gives $x = 4$ or $x = -6$, which means the integers are either 4 and 6 or -4 and -6.

The Sum of the Squares of Two Consecutive Even Integers −4,−6- 4 , - 6−4,−6

The Sum of the Squares of Two Consecutive Even Integers $- 4 , - 6$