Decide what values of the variable cannot possibly be solutions for the equation.
-$$4 x = \sqrt { 1 - 6 x }$$
A) $\left\{ \frac { 1 } { 8 } \right\}$
B) $\left\{ - \frac { 1 } { 2 } \right\}$
C) $\left\{ \frac { 1 } { 4 } \right\}$
D) $\left\{ \frac { 1 } { 2 } \right\}$

Question

Quizplus · Accepted Answer

The square root of a negative number is not a real number, so $6x$ must be less than or equal to 1. Therefore, $x$ must be less than or equal to $\frac{1}{6}$.

Decide What Values of the Variable Cannot Possibly Be Solutions 4x=1−6x4 x = \sqrt { 1 - 6 x }4x=1−6x​

Decide What Values of the Variable Cannot Possibly Be Solutions $4 x = \sqrt { 1 - 6 x }$