Decide what values of the variable cannot possibly be solutions for the equation.
-$$\sqrt [ 3 ] { 3 x + 7 } = - 1$$
A) $\left\{ \frac { 8 } { 3 } \right\}$
B) $\left\{ - \frac { 8 } { 3 } \right\}$
C) $\{ - 2 \}$
D) $\{ - 8 \}$

Question

Quizplus · Accepted Answer

To find the values that cannot possibly be solutions, we first solve the equation: $\sqrt[3]{3x + 7} = -1$. Cubing both sides gives $3x + 7 = -1$. Solving for $x$ yields $3x = -8$, so $x = -\frac{8}{3}$. This means that $-\frac{8}{3}$ is a solution, not a value that cannot be a solution. Since the question asks for values that cannot be solutions and none of the other options are derived from solving the equation, there are no values among the options given that cannot possibly be solutions based on the equation provided.

Decide What Values of the Variable Cannot Possibly Be Solutions 3x+73=−1\sqrt [ 3 ] { 3 x + 7 } = - 133x+7​=−1

Decide What Values of the Variable Cannot Possibly Be Solutions $\sqrt [ 3 ] { 3 x + 7 } = - 1$