Solve for the indicated variable.
-$\frac { 1 } { \mathrm { Q } } = \frac { 1 } { \mathrm {~T} _ { 1 } } + \frac { 1 } { \mathrm {~T} _ { 2 } }$, for $\mathrm { T } _ { 2 }$
A) $\mathrm { T } _ { 2 } = \frac { \mathrm { Q } - \mathrm { T } _ { 1 } } { \mathrm {~T} _ { 1 } \mathrm { Q } }$
B) $\mathrm { T } _ { 2 } = \frac { \mathrm { T } _ { 1 } - \mathrm { Q } } { \mathrm { T } _ { 1 } \mathrm { Q } }$
C) $\mathrm { T } _ { 2 } = \frac { \mathrm { QT } _ { 1 } } { \mathrm {~T} _ { 1 } - \mathrm { Q } }$
D) $\mathrm { T } _ { 2 } = \frac { \mathrm { QT } _ { 1 } } { \mathrm {~T} _ { 1 } + 4 \mathrm { Q } }$

Question

Quizplus · Accepted Answer

To solve for $T_2$, we start with the given equation $\frac{1}{Q} = \frac{1}{T_1} + \frac{1}{T_2}$. Rearranging to isolate $\frac{1}{T_2}$, we get $\frac{1}{T_2} = \frac{1}{Q} - \frac{1}{T_1}$. To find a common denominator and simplify, we have $\frac{1}{T_2} = \frac{T_1 - Q}{QT_1}$. Inverting both sides to solve for $T_2$ gives $T_2 = \frac{QT_1}{T_1 - Q}$.

Solve for the Indicated Variable 1Q=1 T1+1 T2\frac { 1 } { \mathrm { Q } } = \frac { 1 } { \mathrm {~T} _ { 1 } } + \frac { 1 } { \mathrm {~T} _ { 2 } }Q1​= T1​1​+ T2​1​

Solve for the Indicated Variable $\frac { 1 } { \mathrm { Q } } = \frac { 1 } { \mathrm {~T} _ { 1 } } + \frac { 1 } { \mathrm {~T} _ { 2 } }$