Solve the inequality. Write the solution set in interval notation.
-$$| - 3 - 8 x | 6$$
A) $\left( \frac { 9 } { 8 } , - \frac { 3 } { 8 } \right)$
B) $\left( - \frac { 3 } { 8 } , - \frac { 9 } { 8 } \right)$
C) $\left( - \infty , - \frac { 9 } { 8 } \right) \cup \left( \frac { 3 } { 8 } , \infty \right)$
D) $\left( - \infty , \frac { 7 } { 8 } \right) \cup \left( - \frac { 5 } { 8 } , \infty \right)$

Question

Solve the inequality. Write the solution set in interval notation.
-$$| - 3 - 8 x | > 6$$
A) $\left( \frac { 9 } { 8 } , - \frac { 3 } { 8 } \right)$
B) $\left( - \frac { 3 } { 8 } , - \frac { 9 } { 8 } \right)$
C) $\left( - \infty , - \frac { 9 } { 8 } \right) \cup \left( \frac { 3 } { 8 } , \infty \right)$
D) $\left( - \infty , \frac { 7 } { 8 } \right) \cup \left( - \frac { 5 } { 8 } , \infty \right)$

Quizplus · Accepted Answer

To solve the inequality $| - 3 - 8 x | > 6$, we consider two cases: $ - 3 - 8 x > 6$ and $ - 3 - 8 x < -6$. Solving the first gives $x < -\frac{9}{8}$ and the second gives $x > \frac{3}{8}$. Thus, the solution in interval notation is $\left( - \infty , - \frac { 9 } { 8 } \right) \cup \left( \frac { 3 } { 8 } , \infty \right)$.

Solve the Inequality ∣−3−8x∣>6| - 3 - 8 x | > 6∣−3−8x∣>6

Solve the Inequality $| - 3 - 8 x | > 6$