Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-The first marble is red and the second marble is white.
A) $\frac { 3 } { 56 }$
B) $\frac { 3 } { 28 }$
C) $\frac { 3 } { 8 }$
D) $\frac { 3 } { 7 }$

Question

Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-The first marble is red and the second marble is white. 
A) $\frac { 3 } { 56 }$
B) $\frac { 3 } { 28 }$
C) $\frac { 3 } { 8 }$
D) $\frac { 3 } { 7 }$

Quizplus · Accepted Answer

The probability of drawing a red marble first is $ \frac{2}{8} $. After drawing a red marble, there are 7 marbles left, with 3 being white. The probability of drawing a white marble second is $ \frac{3}{7} $. Thus, the combined probability is $ \frac{2}{8} \times \frac{3}{7} = \frac{3}{28} $.

Two Marbles Are Drawn Without Replacement from a Box with 3