Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-Both marbles are red.
A) $\frac { 3 } { 56 }$
B) $\frac { 1 } { 16 }$
C) $\frac { 1 } { 14 }$
D) $\frac { 1 } { 28 }$

Question

Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-Both marbles are red. 
A) $\frac { 3 } { 56 }$
B) $\frac { 1 } { 16 }$
C) $\frac { 1 } { 14 }$
D) $\frac { 1 } { 28 }$

Quizplus · Accepted Answer

The probability of drawing the first red marble is $ \frac{2}{8} $. After drawing one red marble, there is 1 red marble left and 7 marbles in total, so the probability of drawing the second red marble is $ \frac{1}{7} $. Thus, the probability of both events occurring is $ \frac{2}{8} \times \frac{1}{7} = \frac{1}{28} $.

Two Marbles Are Drawn Without Replacement from a Box with 3