Solve the problem.
-A husband and wife have a $\frac { 1 } { 3 }$ probability of passing on brown eyes to their children. If they have four children, what is the probability of none of the children having brown eyes?

Question

Quizplus · Accepted Answer

The probability of not passing on brown eyes to a child is $1 - \frac{1}{3} = \frac{2}{3}$. For four children, the probability that none have brown eyes is $\left(\frac{2}{3}\right)^4 = \frac{16}{81}$, which simplifies to $\frac{1}{81}$.

Solve the Problem 13\frac { 1 } { 3 }31​ Probability of Passing on Brown Eyes to Their Children

Solve the Problem $\frac { 1 } { 3 }$ Probability of Passing on Brown Eyes to Their Children