Based on a sample of size 49 , a $95 \%$ confidence interval for the mean score of all students, $\mu$, on an aptitude test is from $59.2$ to $64.8$. Find the margin of error.
A) $5.6$
B) $0.78$
C) $0.05$
D) $2.8$
E) There is not enough information to find the margin of error.

Question

Quizplus · Accepted Answer

The margin of error is half the width of the confidence interval. The width of the interval is $64.8 - 59.2 = 5.6$, so the margin of error is $5.6 / 2 = 2.8$.

Based on a Sample of Size 49 , A 95%95 \%95%

Based on a Sample of Size 49 , A $95 \%$