Provide a STATEMENT/REASON proof for the congruence.
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Given: $\mathrm { AC } = \mathrm { DC } , \angle \mathrm { BAC } = \angle \mathrm { EDC }$
Prove: $\triangle \mathrm { ACB } \cong \triangle \mathrm { DCE }$

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The Answer of Provide a STATEMENT/REASON proof for the congruence.
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Given: $\mathrm { AC } = \mathrm { DC } , \angle \mathrm { BAC } = \angle \mathrm { EDC }$
Prove: $\triangle \mathrm { ACB } \cong \triangle \mathrm { DCE }$

Provide a STATEMENT/REASON Proof for the Congruence AC=DC,∠BAC=∠EDC\mathrm { AC } = \mathrm { DC } , \angle \mathrm { BAC } = \angle \mathrm { EDC }AC=DC,∠BAC=∠EDC

Provide a STATEMENT/REASON Proof for the Congruence $\mathrm { AC } = \mathrm { DC } , \angle \mathrm { BAC } = \angle \mathrm { EDC }$