Provide a STATEMENT/REASON proof for the congruence.
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Given: $\mathrm { AC } = \mathrm { BD } , \angle \mathrm { ACD } = \angle \mathrm { BDC }$
Prove: $\triangle \mathrm { ACD } \simeq \triangle \mathrm { BDC }$

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The Answer of Provide a STATEMENT/REASON proof for the congruence.
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Given: $\mathrm { AC } = \mathrm { BD } , \angle \mathrm { ACD } = \angle \mathrm { BDC }$
Prove: $\triangle \mathrm { ACD } \simeq \triangle \mathrm { BDC }$

Provide a STATEMENT/REASON Proof for the Congruence AC=BD,∠ACD=∠BDC\mathrm { AC } = \mathrm { BD } , \angle \mathrm { ACD } = \angle \mathrm { BDC }AC=BD,∠ACD=∠BDC

Provide a STATEMENT/REASON Proof for the Congruence $\mathrm { AC } = \mathrm { BD } , \angle \mathrm { ACD } = \angle \mathrm { BDC }$