Solve the equation.
-$7 [ - 6 z - 3 + 5 ( z + 1 ) ] = 4 z + 2$
A) $\{ 9 \}$
B) $\left\{ \frac { 54 } { 11 } \right\}$
C) $\left\{ \frac { 12 } { 11 } \right\}$
D) $\{ 2 \}$

Question

Quizplus · Accepted Answer

Simplify the equation: $7[-6z - 3 + 5(z + 1)] = 4z + 2$ becomes $7[-6z - 3 + 5z + 5] = 4z + 2$. Simplify inside the brackets: $-6z + 5z = -z$ and $-3 + 5 = 2$, so it becomes $7[-z + 2] = 4z + 2$. Distribute the 7: $-7z + 14 = 4z + 2$. Combine like terms: $-7z - 4z = 2 - 14$ gives $-11z = -12$. Solving for $z$ gives $z = \frac{12}{11}$.

Solve the Equation 7[−6z−3+5(z+1)]=4z+27 [ - 6 z - 3 + 5 ( z + 1 ) ] = 4 z + 27[−6z−3+5(z+1)]=4z+2

Solve the Equation $7 [ - 6 z - 3 + 5 ( z + 1 ) ] = 4 z + 2$