Find the mean for the given frequency distribution.
-Find the approximate mean for the grouped frequency distribution. Use the class midpoint to represent each class. Round your answer to two decimal places.
$\begin{array}{c|r}
\text { Score } & \text { Frequency } \
\hline 60-69 & 3 \
70-79 & 12 \
80-89 & 7 \
90-99 & 2
\end{array}$

A) $79.50$
B) $74.50$
C) $78.12$
D) $77.83$

Question

Find the mean for the given frequency distribution.
-Find the approximate mean for the grouped frequency distribution. Use the class midpoint to represent each class. Round your answer to two decimal places.
 $\begin{array}{c|r}
\text { Score } & \text { Frequency } \
\hline 60-69 & 3 \
70-79 & 12 \
80-89 & 7 \
90-99 & 2
\end{array}$

A) $79.50$
B) $74.50$
C) $78.12$
D) $77.83$

Quizplus · Accepted Answer

To find the approximate mean, we first calculate the midpoint for each class, then multiply each midpoint by the class frequency, sum these products, and divide by the total frequency. The midpoints are 64.5, 74.5, 84.5, and 94.5 for the respective classes. The calculations are as follows: $(64.5*3) + (74.5*12) + (84.5*7) + (94.5*2) = 193.5 + 894 + 591.5 + 189 = 1868$. The total frequency is $3 + 12 + 7 + 2 = 24$. Thus, the mean is $1868 / 24 = 77.83$.

Find the Mean for the Given Frequency Distribution Score Frequency 60−69370−791280−89790−992\begin{array}{c|r}\text { Score } & \text { Frequency } \\\hline 60-69 & 3 \\70-79 & 12 \\80-89 & 7 \\90-99 & 2\end{array} Score 60−6970−7980−8990−99​ Frequency 31272​​

Find the Mean for the Given Frequency Distribution $\begin{array}{c|r}\text { Score } & \text { Frequency } \\\hline 60-69 & 3 \\70-79 & 12 \\80-89 & 7 \\90-99 & 2\end{array}$