A population mean is to be estimated from the sample described. Round your answer to one decimal place if necessary. Assume that all confidence intervals use a 95% confidence level.
-Sample size = 3025, sample mean = 244, sample standard deviation = 80 What is the margin of error?
A)2.9
B)0.1
C)1.5
D)8.9

Question

Quizplus · Accepted Answer

The margin of error (E) for a population mean, using a 95% confidence level and given the sample size (n), sample mean ($\bar{x}$), and sample standard deviation (s), can be calculated using the formula $E = z \times \frac{s}{\sqrt{n}}$, where z is the z-score corresponding to the 95% confidence level (approximately 1.96 for a two-tailed test). Plugging in the given values: $E = 1.96 \times \frac{80}{\sqrt{3025}} = 1.96 \times \frac{80}{55} \approx 2.9$.

A Population Mean Is to Be Estimated from the Sample