A poll of 1000 voters in one district showed that 62% of them would favor stricter gun control laws. Find the margin of error for the 95% confidence interval for this study.
A)0.0217
B)0.0307
C)0.001
D)0.0153

Question

Quizplus · Accepted Answer

The margin of error for a proportion in a population can be calculated using the formula $ME = Z \times \sqrt{\frac{p(1-p)}{n}}$, where $Z$ is the Z-score for the desired confidence level (1.96 for 95%), $p$ is the sample proportion (0.62), and $n$ is the sample size (1000). Plugging in the numbers: $ME = 1.96 \times \sqrt{\frac{0.62 \times 0.38}{1000}} \approx 0.0307$.

A Poll of 1000 Voters in One District Showed That