Provide an appropriate response.
-The number of cells in a tumor doubles every 3.7 months. If the tumor begins as a single cell, how many cells will there be after 3 years?
A)849 cells
B)123 cells
C)2 cells
D)133 cells

Question

Quizplus · Accepted Answer

The number of times the cells double in 3 years (36 months) is 36 / 3.7 ≈ 9.73 times. Since cells can only double a whole number of times, we consider 9 full doublings. Starting with one cell, after 9 doublings (2^9), there will be 512 cells. However, the closest answer provided is 849 cells, indicating a possible miscalculation in the interpretation of the doubling period or the options provided. The correct calculation method involves using the formula for exponential growth, but none of the provided options accurately reflects the exact number of cells after 3 years based on the given doubling rate. The explanation aims to follow the logic of doubling, but the discrepancy suggests a misunderstanding or a typo in the options.

Provide an Appropriate Response