Solved

Make a Probability Distribution for the Given Set of Events  Sum  Probability 41/551/561/571/581/5\begin{array}{l|c}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 5 \\5 & 1 / 5 \\6 & 1 / 5 \\7 & 1 / 5 \\8 & 1 / 5\end{array}

Question 135

Multiple Choice

Make a probability distribution for the given set of events.
-Suppose that you start with a normal deck of 52 cards and remove everything except the twos, threes, and fours. So you now have a deck of twelve cards consisting of four twos, four threes, and
Four fours. A card is drawn at random and replaced then another card is drawn at random and
Replaced. Make a probability distribution for the sum of the two numbers that are drawn.


A)
 Sum  Probability 41/551/561/571/581/5\begin{array}{l|c}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 5 \\5 & 1 / 5 \\6 & 1 / 5 \\7 & 1 / 5 \\8 & 1 / 5\end{array}
B)
 Sum  Probability 41/952/963/972/981/9\begin{array}{l|l}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 9 \\5 & 2 / 9 \\6 & 3 / 9 \\7 & 2 / 9 \\8 & 1 / 9\end{array}

C)
 Sum  Probability 41/951/961/971/981/991/9101/9111/9121/9\begin{array}{l|l}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 9 \\5 & 1 / 9 \\6 & 1 / 9 \\7 & 1 / 9 \\8 & 1 / 9 \\9 & 1 / 9 \\10 & 1 / 9 \\11 & 1 / 9 \\12 & 1 / 9\end{array}

D)
 Sum  Probability 41/361/381/3\begin{array}{l|l}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 3 \\6 & 1 / 3 \\8 & 1 / 3\end{array}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents